Question 398558
{{{3(x+7/3)^2=1}}} Start with the given equation.



{{{(x+7/3)^2=(1)/(3)}}} Divide both sides by {{{3}}}.



{{{x+7/3=""+-sqrt(1/3)}}} Take the square root of both sides.



{{{x+7/3=sqrt(1/3)}}} or {{{x+7/3=-sqrt(1/3)}}} Break up the "plus/minus" to form two equations.



{{{x+7/3=sqrt(3)/3}}} or {{{x+7/3=-sqrt(3)/3}}}  Simplify the square root.



{{{x=-7/3+sqrt(3)/3}}} or {{{x=-7/3-sqrt(3)/3}}} Subtract {{{7/3}}} from both sides.



{{{x=(-7+sqrt(3))/(3)}}} or {{{x=(-7-sqrt(3))/(3)}}} Combine the fractions.



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Answer:



So the solutions are {{{x=(-7+sqrt(3))/(3)}}} or {{{x=(-7-sqrt(3))/(3)}}}.



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