Question 398550
the sum of three numbers is 37. The first number is 17 less thsn the second, and the third is six more than two times the second. what is the least of the three numbers?
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Let the numbers be x,y, and z.
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Equations:
x + y + z = 37
x = y-17
z = 2y+6
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Substitute for x and for z and solve for "y":
(y-17) + y + (2y+6) = 37
4y -11 = 37
4y = 48
y = 12
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x = y-17
x = 12-17
x = -5
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z = 2y+6
z = 2*12+6
z = 30
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Cheers,
Stan H.