Question 398522
1. If z=18(cos315°+i*sin315°) in trigonometric form find z in standard form.
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x = 18*cos(315) = 18*cos(-45) = 18*cos(45) = 18[sqrt(2))/2 = 9sqrt(2)
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y = 18*sin(315) = 18*sin(-45) = 18[-sin(45)] = -18[sqrt(2)/2] = -9sqrt(2)
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z = (9sqrt(2))-9sqrt(2)i
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2. If z=4√(3)(cos150°+i*sin150°) in trigonometric form find z in standard form. 
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Go thru the same process.
Remember cos(150) = -cos(30) = -sqrt(3)/2
and sin(150) = sin(30) = 1/2
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Cheers,
Stan H.