Question 398285
   <pre><font size = 3 color = "indigo"><b>
Hi
*[tex \LARGE \ \ \ \ \ \ \ \ \ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
   (x+3)^2 = 4
  x^2 + 6x + 9 = 4
  x^2 + 6x + 5 = 0
  (x+1)(x+5) = 0  x = -1, the largest solution

*[tex \large\ \ log_bx + log_by = log_b(xy) ]
*[tex \large\ \ log_bx - log_by = log_b(x/y) ]
2log[4]x+log[4]3=log[4]x-log[4]2
 *[tex \LARGE\ \ log_4(3x^2) - log_4 (x/2)= 0 ]
 *[tex \LARGE\ \ log_4(6x)= 0 ]    4^0 = 6x      x = 1/6

3^(x+1) = 7^(x-4)
 ln 3^(x+1) = ln 7^(x-4)
(x+1)ln3 = (x-4) ln7
x(ln3 -ln7) = -(4ln7+ln3)
 x = -(4ln7+ln3) /(ln3-ln7)