Question 398271
longer leg  = s +1
hypotenuse =  2s -1
Hence {{{(2s - 1)^2 = s^2 + (s+1)^2}}}
==> {{{4s^2 - 4s + 1 = s^2 + s^2 + 2s + 1}}}
==> {{{2s^2 - 6s  =0}}}
==> 2s(s - 3) = 0 ==> s = 0, 3  ==> s = 3 meters, the measure of the shorter leg, s + 1 = 4 meters, the measure of the longer leg, and 2s  -1 = 5 meters, the measure of the hypotenuse.

Rodney’s scores on his first three business calculus tests were an 80, 63, and an 84. What grade on his fourth test will give him an average of 80?
{{{(80 + 63 + 84 + x)/4 = 80}}} ==> 227 + x = 320 ==> x = 93.