Question 398222
<pre>
y=-x+2

get some points for the line y = -x+2

 x | y
 0 | 
-1 | 
 4 |

x=0            x=-1              x=4
y = -x+2       y = -x+2          y = -x+2
y = -0+2       y = = -(-1)+2     y = -(4)+2
y = 2          y = +1+2          y = -4+2 
               y = 3             y = -2

 x | y
 0 | 2
-1 | 3
 4 |-2

Plot those points and connect them:

{{{drawing(400,400,-5,5,-3,7,
circle(0,2,.07), circle(-1,3,.07), circle(4,-2,.07),
graph(400,400,-5,5,-3,7,-x+1.95))}}}

Now get some points for the other line 3x+3y=12

 x | y
 0 |  
-1 | 
 4 |

  x=0             x=-1             x=4
  3x+3y=12        3x+3y=12         3x+3y=12
3(0)+3y=12     3(-1)+3y=12       3(4)+3y=12
   0+3y=12      -3 + 3y=12         12+3y=12 
     3y=12           3y=15            3y= 0
      y=4             y= 5             y= 0



 x | y
 0 | 4
-1 | 5
 4 | 0

Plot those points and connect them:

{{{drawing(400,400,-5,5,-3,7,
circle(0,2,.07), circle(-1,3,.07), circle(4,-2,.07),
circle(0,4,.1), circle(-1,5,.1), circle(4,0,.1),
graph(400,400,-5,5,-3,7,-x+4),
graph(400,400,-5,5,-3,7,-x+2))}}}

 
The lines do not intersect since they are parallel, so
there is no solution.

Edwin</pre>