Question 398223
Let {{{a}}} = pounds of peanuts in mix
Let {{{b}}} = pounds of cashews in mix
given:
(1) {{{a + b = 10}}} pounds
{{{(360a + 790b) /10 = 532}}} (in cents)
(2) {{{360a + 790b = 5320}}}
Multiply both sides 0f (1) by {{{360}}},
and subtract (1) from (2)
(2) {{{360a + 790b = 5320}}}
(1) {{{-360a - 360b = -3600}}}
{{{430b = 1720}}}
{{{b = 4}}}
and, since
{{{a + b = 10}}}
{{{a = 6}}}
There are 6 pounds of peanuts in mix
There are 4 pounds of cashews in mix
check:
{{{(360a + 790b) /10 = 532}}}
{{{(360*6 + 790*4) /10 = 532}}}
{{{(2160 + 3160)/10 = 532}}}
{{{5320/10 = 532}}}
{{{532 = 532}}}
OK