Question 398207
{{{-3k^(-3)(mn)^3 / p^(-8)}}}


{{{-3(1/k^(3))(mn)^3 / (1/p^(8))}}}


{{{(-3(mn)^3/k^(3))/(1/p^(8))}}}



{{{(-3(mn)^3p^(8))/(k^(3))}}}


so, you  got it right...:-)...{{{-3p^8(mn)^3 /k^3}}}