Question 43192
f(x) = 6x^4 + 2x^3 - 3x^2 + 2 

a. 1/6, -1/6, 1/2, -1/2, 1/3, -1/3, 2/3, -2/3, 1, -1, 2, -2 
b. 1/6, -1/6, 1/2, -1/2, 1/3, -1/3, 2/3, -2/3, 1, -1, 2, -2, 3, -3 
c. 1/6, -1/6, 1/2, -1/2, 1/3, -1/3, 1, -1, 2, -2 
d. 1/2, -1/2, 3/2, -3/2, 1, -1, 2, -2, 3, -3, 6, -6 
e. None of the others 


If p/q is a rational root of f(x) then p divides 2 and q divides 6
Therefore p can be 1,-1,2,-2
and q can be 1,-1,2,-2,3,-3,6,-6

"a" is the answer.  Can you see why?

Cheers,
Stan H.