<PRE><B>Question 398132</B>
Find three consecutive odd integers such that the sum of twice the first, twice the second, and three times the third is 9.
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Odd numbers must be represented as an odd # more than or less than 
an even number.
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1st: 2x-1
2nd: 2x+1
3rd: 2x+3
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Equation:
2(2x-1)+2(2x+1)+3(2x+3) = 9
4x-2+4x+2+6x+9 = 9
14x + 9 = 9
14x = 0
x = 0
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1st: -1
2nd: +1
3rd: 3
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Check:
2(-1)+2(1)+3(3) = 9
checks
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Cheers,
Stan H.</PRE>