Question 398123
The sum of the interior angles of a polygon with n sides is given by:
{{{S[i] = (n-2)180}}} degrees.
The sum of the exterior angles of a "regular" polygon with n sides is given by:
{{{S[e] = n(180-((n-2)180/n))}}} ...and if you simplify this, you get...
{{{S[e] = 180n-180n+360}}}
{{{S[e] = 360}}}degrees.
The measure of one interior angle of a "regular" polygon with n sides is:
{{{A[i] = ((n-2)*180)/n}}}