Question 397986
Assuming that the probability of any ONE entrepreneur getting a score X is normally distributed, the probability of scoring {{{X >= 74}}} is {{{P(X >= 74)=P(Z = (X-73)/9 >= (74-73)/9 = 1/9)}}}. 
Let
{{{alpha = P(X >= 74)= P(Z > = 1/9)}}}, and 
{{{beta = P(X < 74) = 1 - P(Z > = 1/9)}}}.
COMPUTE for these two values {{{alpha}}} and {{{beta}}}.

From here on the binomial distribution takes over.
Thus the probability that at least two of them will score more than 74 on
the CDQ is {{{4C2*alpha^2*beta^2 + 4C3*alpha^3*beta^1 + 4C4*alpha^4}}}.
Compute for this value,and that's it.