Question 398029
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You can't.   All you can say is that the area is in the range:


*[tex \LARGE\ \ \ \ \ \ \ \ \ \ 0\ <\ A_R\ \leq\ \frac{d^2}{2}]


where *[tex \Large d] is the measure of the diagonal.  The maximum area is obtained when the rectangle is a square with side measure *[tex \Large \frac{d\sqrt{2}}{2}]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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