Question 43172
[x^2+x/10]/[2x+4/5]

Invert the denominator and multiply, as follows:
[(x^2+x)/10]*[5/(2x+4)]

Factor where possible:
[x(x+1)/10]*[5/(2(x+2)]

Reduce where possible:
[x(x+1)/2]*[1/(2(x+2)]

[x^2+x]/[4x+8]

Cheers,
stan H.