Question 397952
8x^2+40x+8y^2+24y-60=0

standard form for a circle
(x-h)^2+(y-k)^2=r^2, with (h,k) being the coordinates of the center, and r=radius.
completing squares
8(x^2+5x+25/4)+8(y^2+3y+9/4)=60+50+18=128
divide by 8
(x+5/2)^2+(y+3/2)^2=16

center(-5/2,-3/2) 

r^2=16
r=4
ans: this is a circle with center at (-5/2,-3/2), and radius=4