Question 397940
There is a cubic formula, but I wouldn't bother memorizing it...


You could use Newton's method to find the real zeros of the function. Newton's method defines a recursive sequence


{{{x[n+1] = x[n] - f(x[n])/f^((1)) (x[n])}}} (the website doesn't let me use f'(x) so I used f^(1) (x))


and it can be iterated indefinitely to find real roots.