Question 397952
(8x^2+40x)+(8y^2+24y)-60=0
8(x^2+5x)+8(y^2+3y)-60=0
8((x^2+2*(5/2)x+(5/2)^2)-(5/2)^2)+8((y^2+2*(3/2)y+(3/2)^2)-(3/2)^2)-60=0(/8)
(x+(5/2))^2-(25/4)+(y+(3/2))^2-(9/4)-7.5=0
(x+2.5)^2+(y+1.5))^2=16
{{{(x-a)^2+(y-b)^2=R^2}}} has a circle as a graph with center in (a;b) and radius R
so (x+2.5)^2+(y+1.5)^2=16 has a circle as a graph with center in (-2.5;-1.5) and radius R=4