Question 397940
iF I have 4x^2+5=6x^3 how would i solve for a real number solutions?
4x^2+5=6x^3

the only way I know how to get a real number solution is to do it graphically on a graphing calculator or a computer graphing program.
rearrange the equation and set it to zero

6x^3-4x^2-5=0

enter 6x^3-4x^2-5 into the graphing calculator and you will find that when y=0,
x=1.22342
The other two solutions must be imaginary because the curve crosses the x-axis only once as seen on the graph

Maybe a smarter tutor knows how to get an algebriac solution, but this one is beyond my pay grade.