Question 397786
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Hi
Note:  
(a + 4)(a+2) = a^2 + 6a + 8  |SUM of the inner product(4a) and the outer product(2a) =6a
point being whether whole numbers or fractions, process is the same
{{{(a+1/4)(a + 1/2) = a^2 + (3/4)a + 1/8 }}}
|SUM of the inner product:{{{(1/4)a}}} and the outer product {{{(1/2)a}}}= {{{(3/4)a}}}