Question 43184
{{{p = x + (n-2)y}}}
{{{p - x = x - x + (n-2)y}}} because 2 = 2 can be: 2 - 2 = 2 - 2 as 0 = 0
{{{p - x = (n - 2)y}}}
{{{(p - x)/y = (n - 2)y/y}}} you need to remove the {{{y}}} so it is not distributed
{{{(p - x)/y = n - 2}}}
{{{(p - x)/y + 2 = n - 2 + 2}}}
{{{(p - x)/y + 2 = n}}}