Question 397627
Perpendicular lines have slopes that are negative reciprocals,
{{{m[1]*m[2]=-1}}}
{{{-4*m[2]=-1}}}
{{{m[2]=1/4}}}
So then,
{{{y=mx+b}}}
{{{y=-(1/4)x+b}}}
Use the point (-8,3) to solve for {{{b}}}.
{{{3=-(1/4)(-8)+b}}}
{{{3=2+b}}}
{{{b=1}}}
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{{{highlight(y=-(1/4)x+1)}}}