Question 397411
Chebyshev's Theorem states that {{{P(abs(X - mu) < k*sigma) >= 1 - 1/k^2}}}
{{{mu = 208}}} and {{{sigma = 11}}} ==> {{{P(175 < X < 241)=
P(abs(X - 208) < 3*11 = 33) >= 1 - 1/9 = 8/9}}}.  Hence at least {{{(8/9)*100 = 88.89}}}% of the values will fall between 175 and 241.

The Empirical rule, or the 68-95-99.7 rule, says that 99.7% of the values lie within 3 standard deviations of the mean, given that the values are NORMALLY distributed.  Hence around 99.7% of all values would fall between 175 and 241.