Question 397524
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The area of a triangle is the base times the height divided by 2.  So the area of your triangle BEFORE you triple the height is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ \frac{6h}{2}\ =\ 3h]


If you add 24 to the area, you triple the height:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ +\ 24\ =\ \frac{18h}{2}]


Which can be written:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ \frac{18h}{2}\ -\ 24\ =\ 9h\ -\ 24]


Now that we have two different expressions that both equal A, set them equal to each other.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 9h\ -\ 24\ =\ 3h]


Just solve for *[tex \Large h]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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