Question 43132
x^5 + 3x -7 by x^3 + 1

You are asked to divide x^5 + 3x -7 
by x^3 + 1.

That process is rather hard to show on this site .

Set up the problem as you would any long-division problem.

Divide x^3 into x^5 to get x^2 as the 1st term of the quotient.

Multiply x^2 times (x^3+1)to get x^5+x^2

Subtract this from x^5+3x-7 to get -x^2+3x-7

Since dividing this by x^3+1 would lead to negative
exponents you are finished.

So the result of dividing is x^2; the remainder is -x^2+3x-7

Cheers,
Stan H.