Question 397312
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Hi
y = 12x^3-12x
Finding the zeros of the function
  12x^3 - 12x = 0
  12x(x^2 - 1) = 0
  12x(x+1)(x-1)= 0

  12x = 0   x = 0
  (x+1)=0   x = -1
  (x-1)= 0  x = 1