Question 397301
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Let *[tex \Large x] represent the measure of the angle.  Then the measure of the complement of the angle is *[tex \Large 3x\ -\ 42].  The sum of the measure of an angle and the measure of the angle's complement is *[tex \Large 90^\circ], hence:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ 3x\ -\ 42\ =\ 90]


Solve for *[tex \Large x], then multiply by 3 and subtract 42.  Subtract the result from 90 to check  your work.  That result should be the value of *[tex \Large x]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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