Question 397149
You have a rectangle with length of 9 ft. and width of 7 ft.
 You then have a similar rectangle with a perimeter of 260 ft. What is the length and width of the similar rectangle.
:
You have the right multiplier 8.125, and obtained the right dimensions
:
An easy way to find that: Find the perimeter of the original rectangle; 32 ft
260/32 = 8.125 is the multiplier
:
If you want to make it an algebra exercise; let x = the multiplier
2(9x)+ 2(7x) = 260
You can solve this and find it that way.