Question 397197
Beth was required to make a cross-country flight in training for her pilot's license. When she flew from her home airport, a steady 30 miles per hour wind was behind her, and the trip took 5 hours. When she returned against the wind, the flight took 7 hours. Find the plane's speed in still air and the distance traveled each way.

plane's speed = x mph
..
with wind speed = x+30
against wind = x-30
...
d=rt. d is same so equate the distance
5(x+30)=7(x-30)
5x+150=7x-210
7x-5x=210+150
2x=360
/2
x= 180 mph speed in still air
..
m.ananth@hotmail.ca