Question 397208
The sum of one-half, one-third and one-fourth of a number exceeds the number by 12. The number is

let the number be x
x/2 +x/3+x/4 = x+12
...
LCD = 12
(6x+4x+3x)/12=x+12
13x= 12(x+12)
13x=12x+144
13x-12x=144
x= 144
..