Question 396503
A collection of nickels and dimes total $5.95. If there are 5 times as many nickels as dimes, then how many of each coin is there?


Let the amount of dimes be D


Then the amount of nickels are 5D


Since the coins total $5.95, we then have: .1(D) + .05(5D) = 5.95


.1D + .25D = 5.95


.35D = 5.95


Therefore, D or dimes = {{{5.95/.35}}} = {{{highlight_green(17)}}} 


and nickels = 17 * 5 = {{{highlight_green(85)}}}


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Check
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Dimes: 17 = 17 * 10_______$1.70 

Nickels: 85 = 85 * 5______$4.25 

Total of coins___________$5.95