Question 397153
If {{{x/(2y)=2}}}, then {{{x=4y}}} (multiply both sides by 2y)



So plug this into {{{(3x+8y)/(x-2y)}}} to get {{{(3(4y)+8y)/(4y-2y)}}}, multiply to get {{{(12y+8y)/(4y-2y)}}}, combine like terms to get {{{20y/2y}}} and reduce to get {{{10}}}



So {{{(3x+8y)/(x-2y)=10}}} if {{{x/(2y)=2}}}



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Jim