<PRE><B>Question 397124</B>
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If you choose 12 of the balls, it is possible to select 3 of each of the 4 colors.  Then if you take one more, you will have 4 of whichever color you selected on the 13th ball.  So, 13.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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