Question 397057
Train A and B are traveling in the same direction on parellel tracks. Train A is traveling 80 miles per hour and train B is traveling at 88 miles per hour. Train A passes a station at 6:25 P.M. If train B passes the same station at 6:40 P.M., at what time will train B catch up to train A? 
(Can you inclede in the answer, either A.M. or P.M, thanks)! 
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Train A DATA:
rate = 80 mph ; time =  x minutes ; distance = (x/60)(80) = (4/3)x miles
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Train B DATA:
rate = 88 miles; time = (x-15) minutes; distance = [(x-15)/60]88 miles
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Equation:
distance = distance
(4/3)x = (88/60)(x-15)
Multiply both sides by 60 to get
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80x = 88(x-15)
80x = 88x-88*15
8x = 88*15
x = 11*15
x = 161 minutes = 2 hrs 41 minutes
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6:25PM + 2hrs 41 minutes = 9:05 PM
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Cheers,
Stan H.