Question 397098
Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(2,5\right)]. So this means that {{{x[1]=2}}} and {{{y[1]=5}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(3,-1\right)].  So this means that {{{x[2]=3}}} and {{{y[2]=-1}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(-1-5)/(3-2)}}} Plug in {{{y[2]=-1}}}, {{{y[1]=5}}}, {{{x[2]=3}}}, and {{{x[1]=2}}}



{{{m=(-6)/(3-2)}}} Subtract {{{5}}} from {{{-1}}} to get {{{-6}}}



{{{m=(-6)/(1)}}} Subtract {{{2}}} from {{{3}}} to get {{{1}}}



{{{m=-6}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(2,5\right)] and *[Tex \LARGE \left(3,-1\right)] is {{{m=-6}}}



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