Question 397057

Train B passes the station at 6:40 PM. I know that train A
passed the station 15 min ago at 6:25 PM.
In 15 min, train A has travelled {{{80*(1/4) = 20}}} mi
Let {{{d}}} = distance train B has to go to catch train A.
Then {{{d - 20}}} is the distance train A must go to
meet B.
For train A:
{{{d - 20 = 80t}}}
For train B:
{{{d = 88t}}}
Substitute {{{d}}} in 2nd equation into 1st equation
{{{88t - 20 = 80t}}}
{{{8t = 20}}}
{{{t = 5/2}}} hr
train B will catch train A in 2.5 hrs after train B passed station.
6:40 PM + 2.5 = 9:10 PM