Question 396749
{{{x }}}= one number
{{{(x + 2)}}} = the other number

{{{x(x + 2) = x + (x + 2) + 7}}}

{{{x^2 + 2x = 2x + 9 }}} 

I am missing something....just continue


{{{x^2 + 2x = 2x + 9 }}} ...add {{{-2x}}}} to the both sides

{{{x^2 + 2x - 2x = 2x - 2x + 9 }}} 

{{{x^2 +cross( 2x) -cross( 2x) = cross( 2x) -cross( 2x) + 9 }}}

{{{x^2  =  9 }}}

{{{x  = sqrt( 9 )}}}


{{{x}}}=+-{{{(3)}}}


 so, your numbers are:

3,5.....first solution

and

-3, -1........second solution


check both:

{{{3(3 + 2) = 3 + (3 + 2) + 7}}}


{{{3(5) = 3+ 5 + 7}}}

{{{15 = 15}}}

{{{-3(-3 + 2) = -3 + (-3 + 2) + 7}}}

{{{-3(-1) = -3 + (-1) + 7}}}



{{{3 = -3 -1 + 7}}}

{{{3 = -4 + 7}}}

{{{3 = 3 }}}