Question 396646
If the sum of 2 numbers is -14 and their product is 32, what are the numbers?

Let x = one number
Let x - 14 = the other number

x(x - 14) = 32
x^2- 14x + 32

(x - 6) (x-8) 

The two numbers are -8 and -6
I know that -8 + -6 = -14 but when I plug in the numbers that do not equal 32.  What am I not doing correct?
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Let x = one number
Let -14 - x = the other number

x(-x - 14) = 32
-x^2 - 14x - 32 = 0
x^2 + 14x + 32 = 0
*[invoke solve_quadratic_equation 1,14,32]
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x = -7 ± sqrt(17)
One number is -7 + sqrt, the other is -7 - sqrt
No integer solutions.
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I would check for a typo.
If the sum is -12, then it's -4 and -8.