Question 396592
call the integers {{{a}}}, {{{b}}}, and {{{c}}}
given:
{{{a + b + c = 123}}}
{{{b = 2a + 2}}}
{{{c = 3a - 5}}}
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By substitution:
{{{a + 2a + 2 + 3a - 5 = 123}}}
{{{6a -3 = 123}}}
{{{6a = 126}}}
{{{a = 21}}}
and, since
{{{b = 2a + 2}}}
{{{b = 42 + 2}}}
{{{b = 44}}}
and
{{{c = 3a - 5}}}
{{{c = 63 - 5}}}
{{{c = 58}}}
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The integers are 21, 44, and 58