Question 396503
A collection of nickels and dimes total $5.95. If there are 5 times as many nickels as dimes, then how many of each coin is there?
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Quantity Eq: n = d + 5
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Value Eq: 5n + 10d = 595 cents
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Substitute for "n" and solve for "d":
5(d+5) + 10d = 595
15d + 25 = 595
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15d = 570
d = 30 (# of dimes)
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Solve for "n":
n = d +5
n = 30+5
n = 35 (# of nickels)
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Cheers,
Stan H.