Question 396187
We have {{{y = tan^(-1) (ln x + (x^2 + 1)^(1/2))}}}


Note that the derivative of arctan x is {{{1/(1+x^2)}}}. Using this,


{{{dy/dx = (1/(ln x + (x^2 + 1)^(1/2))) (1/x + (x)(x^2 + 1)^(-1/2))}}} (note that we have to take the derivative of the inside due to the chain rule)