Question 396327
what's the equation for the line 
perpendicular to y=6x+3 that contains (-6,2)
---
The given line has a slope of 6.
--------------------------------------
Any line perpendicular to it must
have a slope of -1/6
--------------------------
Form:
y = mx+b
Substitute and solve for "b":
2 = (-1/6)*-6 + b
2 = 1+b
b = 1
--------------------
Equation:
y = (-1/6)x + 1
=====================
Cheers,
Stan H.
===================