Question 396298
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Hi
difference is 10
Let x and (x-10) represent the numbers
question states***
 x(x-10) = 96
solving for x
 x^2 - 10x = 96
x^2 - 10x - 96 = 0
(x - 16)(x + 6) = 0 Note:SUM of the inner product(-6x) and the outer product(6x) = -10x
(x - 16)=0
  x = 16     this pair of Numbers are 16 and 6  | 6*16 = 96
(x + 6) = 0
  x = -6    this pair Numbers are -6 and -16    | -1*-16 = 96