Question 396194
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Hi
{{{4/(6-x) + x^2/(6-x) = 2}}} |multiplying @ term by (6-x) so as all denominators=1
  4 + x^2 = 2(6-x)
solving for x
  4 + x^2 = 12 - 2x
 x^2 + 2x - 8 = 0 
factoring
(x+4)(x-2)= 0  Note:SUM of the inner product(4x) and the outer product(-2x) = 2x
(x+4)=0    x = -4
(x-2)= 0
   x = 2