Question 396150


{{{(4t)/(t^2-1)+(t)/(t-1)}}}......you can factor {{{(t^2-1)= (t+1)(t-1)}}}


{{{(4t)/(t^2-1)+(t)/(t-1)}}}....common denominator is {{{(t+1)(t-1)}}}


{{{(4t+(t)(t+1))/(t+1)(t-1)}}}


{{{(4t+t^2+t)/(t+1)(t-1)}}}


{{{(t^2 + 5t)/(t+1)(t-1)}}}


{{{t(t + 5)/(t+1)(t-1)}}}