Question 395073
whatis the y-coordinate of the vertex of the parabola that is given? x=-1.5(y-1)^2+4

This parabola is of the form, x=A(y-k)^2+h, (h,k) being the (x,y) coordinates of the vertex.

Just by inspection of the equation, you should see that this is a parabola with its axis of symmetry horizontal, opening to the left, with the vertex at (4,1).
The larger the coefficient, A, the narrower the parabola.

ans: The y-coordinate of the vertex=1

see the following graph:1+(x-4)/-(1.5))^.5

{{{ graph( 300, 200, -6, 10, -10, 10, 1+((x-4)/-1.5)^.5,1-((x-4)/-1.5)^.5)}}}