Question 396007
Sub y for sin(x)
{{{8y^3 - 18y^2 + 13y - 3 = 0}}}
You can see that 8+13 = -(-18-3) so f(-1) = 0 and y=1 is a zero.
Divide by (y-1) and solve the quadratic.
Sub sin(x) for y.