Question 395938
I am having so much trouble with this one questions. I don't understand graphing equations. Can you please help me? The question is:
 Solve the following system of equations graphically for all values of x and y.
y=(x+3) to the second -4 and 2y-10=4x. 

y=(x+3)^2-4
y=x^2+6x+9-4
y=x^2+6x+5
A parabola opening upwards
(x=0, y=5)
(x=1,y=12)
..
2y-10=4x
2y=4x+10
y=2x+5
(x=0,y=5)
(x=1,y=7)
...
Generate values of y for various values of x for both equations and draw the graph.
{{{graph(300,300,-6,6,-6,6,y=(x^2+6x+5),(2x+5))}}}
as you will see from the graph the points of intersection are (0,5) &(-4,-3)
...
m.ananth@hotmail.ca