Question 395956
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 6|x|\ +\ 22\ =\ 4]


Add -22 to both sides


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 6|x|\ =\ -18]


Multiply both sides by *[tex \Large \frac{1}{6}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ |x|\ =\ -3]


Now you have something in the LHS that is always positive or zero and something in the RHS that is clearly less than zero.  No solution.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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