Question 395819
{{{(9/5)x+2=(7/3)x+10}}} Start with the given equation.



{{{15((9/cross(5))x+2)=15((7/cross(3))x+10)}}} Multiply both sides by the LCD {{{15}}} to clear any fractions.



{{{27x+30=35x+150}}} Distribute and multiply.



{{{27x=35x+150-30}}} Subtract {{{30}}} from both sides.



{{{27x-35x=150-30}}} Subtract {{{35x}}} from both sides.



{{{-8x=150-30}}} Combine like terms on the left side.



{{{-8x=120}}} Combine like terms on the right side.



{{{x=(120)/(-8)}}} Divide both sides by {{{-8}}} to isolate {{{x}}}.



{{{x=-15}}} Reduce.



----------------------------------------------------------------------


Answer:


So the solution is {{{x=-15}}} 



If you need more help, email me at <a href="mailto:jim_thompson5910@hotmail.com?Subject=Algebra%20Help">jim_thompson5910@hotmail.com</a>


Also, feel free to check out my <a href="http://www.freewebs.com/jimthompson5910/home.html">tutoring website</a>


Jim