Question 395766
   <pre><font size = 3 color = "indigo"><b>
Hi
solving the following quadratic equation by factoring
x^2+4x = 12
x^2+4x -12 = 0  |must set to zero prior to factoring
factoring
(x ± __)(x ± __)|Ask ourselves what 2 numbers have a product of 12 and difference or 4
(x+6)(x-2)=0 Note:SUM of the inner product(6x) and the outer product(-2x) = 4x
(x+6)=0
  x = -6
(x-2)=0  
  x = 2